Question

Since x^2+8x-15 cant be factored perfectly, what's the next step?

Answer 1

quadratic formula?

Answer 2

u can use the quadratic formula to find x just let the equation be 0 before u use it.

Answer 3

u MUST try the quadratic formula: if \(ax^2+bx+c=0\) then
\[ \large x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} \]

Answer 4

a=1; b=8 c=-15

Answer 5

yes

Answer 6

and then you substitute a b c into the formula and you'll have x!

Answer 7

yes. sorry, busy elsewhere.