Question

Prove that (1+3ω+ω^2) (1+ω+2ω^2)=2

Answer 1

whats 1+w^2 from
1+w+w^2=0 ??

Answer 2

i think we have to multiply all

Answer 3

but it can be simplified without multiplication.....

Answer 4

how

Answer 5

(1+3w+w^2)= ((1+w^2)+3w)
now from 1+w+w^2=0,we have (1+w^2)=-w
so, ((1+w^2)+3w) = (-w+3w) = 2w
got this?
can u do the same for (1+ω+2ω^2)

Answer 6

(1+3ω+ω^2)(1+ω+2ω^2)
arranging it:
(1+ω^2+3ω)(1+ω+2ω^2)
putting formulas:
((-ω)+3ω) ((-ω^2)+2ω^2)

Answer 7

Simplify the terms in the bracket..

Answer 8

u are on right track,go on...

Answer 9

*brackets

Answer 10

(2ω)(ω^2)

Answer 11

You can further simplify it, I believe.

Answer 12

2ω^3=2

Answer 13

You did it ...

Answer 14

if theres a problem in solving further questions i'll ask it so be there thanks