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(a4/3 over a1/2) 2/5 to the side
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\[{a{4\over3} \over a{1\over2}}={2\over5} \] ?
yep
It says to perform the operations and simplify. Leave answers exponential form.
i think there's no =
4a/3/a/2=2/5, 3a/8a=2/5,
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\[\huge \left(\frac{a^{\frac 43}}{a^\frac 12} \right) \frac 25\]
ahh...
yep that's it Igbasallote
(3a/8a)^2/5,
how you got that
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nvm it's wrong
first, you can multiply 2/5 to both 4/3 and 1/2
a^(8/15)/a^(2/10)
10.12.2
this the last one
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|dw:1345794064086:dw|this was some straight pellet in the book smh
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