Where do I begin in a problem like this: y^2+3yz-8z-4x=0? where I have to solve for 0

Question

ghazi · Answer

there are three variables but one equation ...so how you gonna get answer for one variable

anonymous · Answer

@ghazi ?

anonymous · Answer

What do you mean by "solve" for 0? You can't solve for a number. You already know what it is. Solve means you find out the value of an unknown, or put in terms of an unknown.

ghazi · Answer

x, y and z are three variable but you've got just one equation....how you gonna get the answer for each variable...the only option is to get one in terms of other

anonymous · Answer

@aseeran oh im sorry i have to solve for 'z'

ghazi · Answer

then separate out z from the equation

anonymous · Answer

y^2+3yz-8z-4x=0
3yz-8z=y^2+4x
z(3y-8)=(-y^2+4x)
z=(-y^2+4x)/(3y-8)

anonymous · Answer

i got z=4x-y^2/3y-8

ghazi · Answer

$$y^2 +3yz-8z-4x=0$$ then $$z(3y-8)=4x+y^2$$

ghazi · Answer

$$z=\frac{ 4x+y^2 }{ 3y-8 }$$

anonymous · Answer

@sarah70 yeah ur answer is also fine

anonymous · Answer

ok thanks guys

ghazi · Answer

:)