Question

Where do I begin in a problem like this: y^2+3yz-8z-4x=0? where I have to solve for 0

Answer 1

there are three variables but one equation ...so how you gonna get answer for one variable

Answer 2

@ghazi ?

Answer 3

What do you mean by "solve" for 0? You can't solve for a number. You already know what it is. Solve means you find out the value of an unknown, or put in terms of an unknown.

Answer 4

x, y and z are three variable but you've got just one equation....how you gonna get the answer for each variable...the only option is to get one in terms of other

Answer 5

@aseeran oh im sorry i have to solve for 'z'

Answer 6

then separate out z from the equation

Answer 7

y^2+3yz-8z-4x=0
3yz-8z=y^2+4x
z(3y-8)=(-y^2+4x)
z=(-y^2+4x)/(3y-8)

Answer 8

i got z=4x-y^2/3y-8

Answer 9

\[y^2 +3yz-8z-4x=0\] then \[z(3y-8)=4x+y^2\]

Answer 10

\[z=\frac{ 4x+y^2 }{ 3y-8 }\]

Answer 11

@sarah70 yeah ur answer is also fine

Answer 12

ok thanks guys

Answer 13

:)