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If f(x) = 3x + 1 and g(x) = 2x − 4, find f[g(2)]. 25 4 0 1
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first find g(2)
then the value which comes substitute it
g(2)=2(2)-4 and f[g(2])= 3[g(2)] + 1
im still confused
g(x) is your inside function, so you plug in 2 there
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what is the value of g(2) @isaiahw.
4f?
g(2) = 2x2-4 = 0
thus f(g[2]) = f(0) = 3x0 + 1 = 1
First get g(2) from g(x) given then you get a value.. put that value in f(x) and calculate
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