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Mathematics 11 Online
OpenStudy (anonymous):

solve inequalities 3<|5-2x|<5

OpenStudy (lgbasallote):

hint: just solve for x in: 3 < 5 - 2x < 5 and -3> 5 - 2x > -5 does that help?

OpenStudy (anonymous):

that part i know

OpenStudy (lgbasallote):

so what part dont you know?

OpenStudy (anonymous):

what is the next step

OpenStudy (lgbasallote):

solve for x for example: 3 < 5- 2x < 5 first step...subtract 5 from all sides \[\implies 3 - 5 < 5 - 5 - 2x < 5 - 5\] combine like terms \[\implies - 2 < -2x < 0\] now divide all sides by - 2 \[\implies 1 > x > 0\] got it?

OpenStudy (anonymous):

yes my mistake was to subtract 3 from both sides, is there a rule that says i should take the right hand side value

OpenStudy (lgbasallote):

what do you mean by take the right hand side value?

OpenStudy (lgbasallote):

oh...i see what you meant

OpenStudy (lgbasallote):

that was purely coincidental...i wasnt "taking the right hand side value"...i was "taking the middle side value" see the objective is to get x alone...so the first step is to subtract 5 so the middle will just be -2x make sense?

OpenStudy (lgbasallote):

then according to the rule of inequalities, what i do to one side, i do to all sides

OpenStudy (anonymous):

that makes clear sense, i just don,t know what id do without you guys here at open study thanks again and again

OpenStudy (lgbasallote):

welcome :D

OpenStudy (anonymous):

i just joined your fan list

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