Find the slope, if possible, of the line passing through each pair of points. (2,-1) and (6, 3)
It passes through but I do not understand, can someone explain?
There are a few ways of finding the slope: 1. Directly (using slope formula) 2. Graphically (using rise/run) 3. Algebraically (using y = mx + b)
algebraically please if you don't mind
If you want to find it algebraically, you have to insert each point, one at a time, into the equation y = mx + b. Doing that, you'll get -1 = 2m + b 3 = 6m + b
Oops I am sorry I have to use the slope formula.
Okay, then use this slope formula: \[m = \frac{y_2 - y_1}{x_2 - x_1}\]
slope = (y2 - y1)/(x2 - x1)?
slope = (3 - (-1))/(6 - 2) slope = (3 + 1)/4 slope = 4/4 slope = 1
I think this is right
Good job. Now, here's a challenge. See if you can figure it out the algebraic way
good golly I want to learn to like algebra
I will try but I have more homework to do.
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