(x-3)^2 Pleasee Help :)

Question

hartnn · Answer

$$(a-b)^2=a^2+2ab+b^2$$
put b=3

anonymous · Answer

huh? i dont understand

hartnn · Answer

that was the formula ,u just have to put b=3 like this:
$$a^2+2*3*a+3^2$$

now u just have to find 2*3 and 3^2=3*3....

anonymous · Answer

ohh okay how do you do that?

anonymous · Answer

nvm blond moment i know how to do that part

anonymous · Answer

a^2+6*a+9

hartnn · Answer

correct :)

anonymous · Answer

i still have to combine right?

hartnn · Answer

thats your final answer
a^2+6*a+9

anonymous · Answer

so you dont have to combine anhything?

anonymous · Answer

atleat the final asnwer should be a^2+15*9

hartnn · Answer

no u cannot different terms...6 has a with it,9 is constant..
u can combine like terms only.....like 2a+3a=5a and 10+20=30.....

phi · Answer

so you dont have to combine anhything?

hartnn gave you a short cut.  if you used FOIL
on (x-3)(x-3)  you would get 4 terms, 2 of which combine 
x^2-3x-3x+9
now combine the -3x -3x

phi · Answer

btw, that middle term should be negative.

phi · Answer

If you know how, I would do FOIL to get the answer. It is good practice.