Which statement describes the translation of
y= -1/2(x-2)^2 from standard position?
Moved up and to the right.
Moved up and to the left.
Moved down and to the left.
Moved down and to the right.
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OpenStudy (anonymous):
Trigonometry: Angles
Standard Position
Angles can exist anywhere in the coordinate plane where two rays share a common vertex. If this vertex is at the origin of the plane and the initial side lies along the positive $x$-axis, then the angle is said to be in standard position.
OpenStudy (anonymous):
s which statement would it be?
OpenStudy (anonymous):
if tell you if y=-1 which quadrant it in . 1st 2nd 3ed or 4th ???????
OpenStudy (anonymous):
3rd and 4th. it's a straight line
OpenStudy (anonymous):
ok good.
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OpenStudy (anonymous):
look at the equation carefully and see!! \[y=-\frac{ 1 }{ 2(x-2)^{2} }\]
OpenStudy (anonymous):
(X-2)^2 =???
OpenStudy (anonymous):
x^2 -4x+4 right!!
OpenStudy (anonymous):
so -1 tells us its in 3rd or 4th so we know that!!
what can we do now!!
OpenStudy (anonymous):
idk
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OpenStudy (anonymous):
2(x^2 -4x+4)=2x^2-8x+8 right
OpenStudy (anonymous):
this is quadratic equation right!
OpenStudy (anonymous):
tell me if you dont undertand me plz
OpenStudy (anonymous):
yes it is
OpenStudy (anonymous):
find it roots and you would know.
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OpenStudy (anonymous):
find the roots of which equation?
OpenStudy (anonymous):
2x^2-8x+8
OpenStudy (anonymous):
1, 1/2, 2, 4, 8
OpenStudy (anonymous):
hello?
OpenStudy (anonymous):
root is 2
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OpenStudy (anonymous):
o
OpenStudy (anonymous):
do you have the book answer??
OpenStudy (anonymous):
no
OpenStudy (anonymous):
OpenStudy (anonymous):
what you have written and what you have in the image are two different equations !!
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OpenStudy (anonymous):
well this was the actual question. my bad!!!
OpenStudy (anonymous):
the attachment
OpenStudy (anonymous):
Regardless what i showed you should make you answer the question.
OpenStudy (anonymous):
the 1st one
OpenStudy (anonymous):
?? "the 1st one"
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OpenStudy (anonymous):
the 1st choices out of the 4 i provided
OpenStudy (anonymous):
Moved up and to the right.
OpenStudy (anonymous):
ok do the following . get a graphic calculator or software and plug in you equation.see for you self as am seing know, its not 1st choices. i hope am wrong so i learn something new here. i really do!!
OpenStudy (anonymous):
plug in the equation from the question, or 2x^2-8x+8?
OpenStudy (anonymous):
plug this y=-1/2 (x-2)^2 -(2)
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OpenStudy (anonymous):
OpenStudy (anonymous):
so how can it be Moved up and to the right
OpenStudy (anonymous):
ok, well fine, i'm wrong...
OpenStudy (anonymous):
am not here help . i hope i did that.
OpenStudy (anonymous):
hope u did what?
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OpenStudy (anonymous):
sorry
i mean am here to help . i hope i did that
OpenStudy (anonymous):
|dw:1345942197493:dw|
OpenStudy (anonymous):
so it can be moved down then to the right?
OpenStudy (anonymous):
thats what i think.
OpenStudy (anonymous):
|dw:1345942387443:dw|
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