Question

I was working on an MVC problem but forgot my trig: \(\sin(\pi-x) = ?\). It's like negative cosine or something, right?

Answer 1

I think it's regular sine....

Answer 2

yes

Answer 3

Yeah probably b/c sin(pi-x) = -sin(x-pi), and that's just flip n' shift

Answer 4

i means yes, it is sine

Answer 5

lol ok

Answer 6

@satellite73 while you're here - is there anyway of simplifying
\[\sin(\arcsin(c_1\sin\Phi)+\alpha)\]
Maybe with the sum of angles for sines we can cancel out a sin/arcsin term - or will we be stuck with a cos(arcsin) term?

Answer 7

nvm ill ask a question seperately.