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If S is any point in the interior of triangle PQR then prove that SQ + SR < PQ + QR.
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|dw:1345956288365:dw|
someone please help!!
please!!!
sorry can u check it plz... i have some doubt on it SQ + SR < PQ + QR or SQ + SR < PQ + PR
sorry its SQ + SR < PQ + PR.
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Does it help @pratu043 ??? \[\LARGE{s=90^o+{1 \over 2} \angle a}\]
was wondering if i could use vectors to proof it? or u want basic trigonometries?
the perimeter of tri PQR > the perimeter of tri SQR because S is inside PQR. in other word PQ+QR+PR > SQ+QR+SR take out the positive amount QR from both side PQ+PR > SQ+SR
Thank you @TheMind
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