Question

How do I solve the following simultaneous equation: y = x^2 and y = 5x - 6

Answer 1

x2-2x-3x+6=0
x(x-2)-3(x-2)=0
(x-2)(x-3)=0

Answer 2

How did you work that out?

Answer 3

Do you know about factorization ??

Answer 4

Yes, but all we were told to use is the substitution method

Answer 5

Here firstly we use Substitution Method only..

See you have :

\[y = x^2\]

Answer 6

In second equation:

\[y = 5x - 6\]

Here put that value of y..

\[x^2 = 5x - 6\]

Getting ??

Answer 7

Oh yes