A shell leaves a mortar with a muzzle velocity of 500 ft/s directed upward at 60 degrees with the horizontal. Determine the position of the shell and its resultant velocity 20 s after firing. how high will it rise?

Question

xishem · Answer

Try breaking up the initial velocity vector into its horizontal and vertical components and working with them separately, only combining them when you need to (to find the resultant velocity at t=20s).

shane_b · Answer

First draw a picture so you can visualize it.  Then as mentioned above, determine the velocity in the y direction:$$\large V_y=500sin (\theta)=?$$Once you know the initial Vy above, you can solve for the height at time t using the kinematic equation:$$d=V_it+\frac{1}{2}at^2$$plugging in -32ft/s^2 for the acceleration and 20s for the time.

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