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(n/6)^k-((n-1)/6)^k*(1-(n/6)^k) can I simplify this? I want to turn it into a sequence with a sigma notation but there's supposed to be a "cleaner" way of expressing it.
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\[(\frac{n}{6})^k-(\frac{n-1}{6})^k \times (1-(\frac{n}{6})^k)\]?
exactly.
actually wait.
I should have probabily chosed a different letter for one of the ks, they're not always the same.
the two ks on the left side of the multiplication sign can be different than the one on the right side.
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I cant edit it somehow i dont know whats wrong. But its the same, just (n/6)^q-((n-1)/6)^q*(1-(n/6)^k)
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