Mathematics
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OpenStudy (anonymous):
f(x)={x^2+2x x<=-1}
{x+8 x>-1}
find f(-4)
f(-1)
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jimthompson5910 (jim_thompson5910):
let's find f(-4) first
jimthompson5910 (jim_thompson5910):
f(-4) means find f(x) when x = -4
OpenStudy (anonymous):
I solved f(6) and got 14.. but got the others wrong.
jimthompson5910 (jim_thompson5910):
what did you get for f(6)?
OpenStudy (anonymous):
my answer is 14 and I got it right.
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jimthompson5910 (jim_thompson5910):
keep in mind that when x = -4, we're looking at the first piece (since x <= -1 here)
jimthompson5910 (jim_thompson5910):
f(6) = 14 is correct
OpenStudy (anonymous):
so I just plug in right?
jimthompson5910 (jim_thompson5910):
because when x = 6, which is greater than -1, we look at the corresponding piece x+8
jimthompson5910 (jim_thompson5910):
but when x = -4, we look at the first piece since f(x) = x^2 + 2x when x <= -1
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OpenStudy (anonymous):
-24?
jimthompson5910 (jim_thompson5910):
f(x) = x^2 + 2x
f(-4) = (-4)^2 + 2(-4)
f(-4) = 16 + 2(-4) <<--- This is where you made your mistake
f(-4) = 16 - 8
f(-4) = 8
jimthompson5910 (jim_thompson5910):
(-4)^2 = 16 and NOT (-4)^2 = -16
OpenStudy (anonymous):
gahh, okay.
jimthompson5910 (jim_thompson5910):
that's ok, it gets a lot of people
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OpenStudy (anonymous):
thank you!
jimthompson5910 (jim_thompson5910):
you're welcome