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OpenStudy (anonymous):
(Algebra II) x/a - 5 = b
Solve for X, find any restrictions.
Please help!!
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jimthompson5910 (jim_thompson5910):
Is the equation
\[\Large \frac{x}{a} - 5 = b\]
OR
\[\Large \frac{x}{a - 5} = b\]
??
OpenStudy (anonymous):
It's the first equation :)
OpenStudy (anonymous):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
start by adding 5 to both sides
\[\Large \frac{x}{a} - 5 = b\]
\[\Large \frac{x}{a} -5+5= b+5\]
\[\Large \frac{x}{a} = b+5\]
jimthompson5910 (jim_thompson5910):
what's next?
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OpenStudy (anonymous):
@jim_thompson5910 I wanna say multiply each side by something, I think multiply by x or a on both sides but I'm not sure.
jimthompson5910 (jim_thompson5910):
you want to keep 'x' on the left side
jimthompson5910 (jim_thompson5910):
so you have to multiply both sides by 'a'
OpenStudy (anonymous):
@jim_thompson5910 Ahhh okay :)!
jimthompson5910 (jim_thompson5910):
\[\Large \frac{x}{a} = b+5\]
\[\Large a\left(\frac{x}{a}\right) = a(b+5)\]
\[\Large \cancel{a}\left(\frac{x}{\cancel{a}}\right) = a(b+5)\]
\[\Large x = a(b+5)\]
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jimthompson5910 (jim_thompson5910):
Optionally, you can distribute the right side, but it's not necessary
OpenStudy (anonymous):
@jim_thompson5910 I see it now, thank you very much!! :) Helped a lot. I'll try to apply that to my other problems as well! :)
jimthompson5910 (jim_thompson5910):
alright great, yw
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