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@helder_edwin
I think it has to be etiher B or d
the plane perpendicular to the vector (1,-1,3) are those that satisfy \[ \large \begin{pmatrix} x& y & z \end{pmatrix} \begin{pmatrix} 1\\ -1\\ 3 \end{pmatrix}=0 \]
forget the constant for a moment
this gives you \[ \large x-y+3z=0 \]
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How about the constant?
Would you add the 3 to get it to equal 0?
now the plane is supposed to pass through (1,1,1) then replacing (x,y,z)=(1,1,1) u get \[ \large 1-1+3\cdot1=3 \]
subtract*
choose between A and B
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B
right?
yes
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