Decide which part of the quadratic formula tells you whether the quadratic equation can be solved by factoring.
−b b2 − 4ac 2a
Use the part of the quadratic formula that you chose above and find its value given the following quadratic equation:
2x2 + 7x + 3 = 0
Help me? PLEASE!
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jimthompson5910 (jim_thompson5910):
Let D = b^2 − 4ac
This is known as the discriminant
jimthompson5910 (jim_thompson5910):
If the discriminant D is a perfect square, then ax^2 + bx + c can be factored
OpenStudy (rositaluv):
Can you explain the factoring process to me? I am having trouble?
jimthompson5910 (jim_thompson5910):
Compare
2x^2 + 7x + 3
to
ax^2 + bx + c
OpenStudy (rositaluv):
I wouldn't use quadratic formula would I?
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jimthompson5910 (jim_thompson5910):
what are the values of 'a', 'b' and 'c'?
jimthompson5910 (jim_thompson5910):
You can if you want
OpenStudy (rositaluv):
a would be 2x^2? I am completely clueless
jimthompson5910 (jim_thompson5910):
a = 2, b = 7 and c = 3
OpenStudy (rositaluv):
ahh ok so know I have 2x^2 +7x+3 would do I do with that?
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jimthompson5910 (jim_thompson5910):
So
D = b^2 - 4ac
D = 7^2 - 4(2)(3) ... Plug in a = 2, b = 7 and c = 3
D = 49 - 24
D = 25
jimthompson5910 (jim_thompson5910):
is 25 a perfect square?
OpenStudy (rositaluv):
Yes
jimthompson5910 (jim_thompson5910):
so 2x^2 + 7x + 3 can be factored
OpenStudy (rositaluv):
And the ending value is?
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jimthompson5910 (jim_thompson5910):
25
jimthompson5910 (jim_thompson5910):
they don't want you to factor, they just want to know if it's possible to factor or not
jimthompson5910 (jim_thompson5910):
they just want the value of b^2 - 4ac
OpenStudy (rositaluv):
I understand how you got the answer it is just they give me a blank to type the answer in and I'm not sure what the correct thing to put in it is.
jimthompson5910 (jim_thompson5910):
you type in 25
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jimthompson5910 (jim_thompson5910):
that's the final value of b^2 - 4ac
jimthompson5910 (jim_thompson5910):
where a = 2, b = 7 and c = 3
OpenStudy (rositaluv):
ok thank god for your help you are a lifesaver! :D
jimthompson5910 (jim_thompson5910):
you're welcome
OpenStudy (rositaluv):
Got a 100 thanks to you! I won't fail Algebra! tehe;)
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jimthompson5910 (jim_thompson5910):
well you did most of the work, I only helped out with 1 problem
jimthompson5910 (jim_thompson5910):
congrats on getting a perfect score
OpenStudy (rositaluv):
Yeah I know its just thats like the first 100 in a while thanks Again! :)