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OpenStudy (anonymous):
75x^3-65x^2+10x
OpenStudy (mathlegend):
First think what can all these numbers be divided by?
OpenStudy (anonymous):
5
OpenStudy (mathlegend):
Good and all the numbers have the variable 'x' next to them right? So lets say 5x
OpenStudy (mathlegend):
So lets factor that out
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OpenStudy (mathlegend):
75/5 = ?
-65/5 = ?
10/5 = ?
OpenStudy (anonymous):
its 5x(15x^2-13x+2)
OpenStudy (mathlegend):
Good
OpenStudy (mathlegend):
Now what I like to use from here is what is known as the AC method
OpenStudy (mathlegend):
A= 15
B= -13
C= 2
A*C= ? (When multiplying 15 and 2)
+B= ? (Rewrite 13... but think when using those two numbers above when does it equal -13)
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OpenStudy (mathlegend):
Do you understand that part?
OpenStudy (anonymous):
kind of
OpenStudy (mathlegend):
Okay well in the parentheses we had 15x^2-13x+2 right?
Now in textbooks this is written with letters like this.."ax^2+bx+c"
OpenStudy (mathlegend):
So you see where I pulled A, B, and C from.
15x^2-13x+2
ax^2+bx+c
OpenStudy (anonymous):
so is 15x^2-13x+2 the answer?
:0
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OpenStudy (mathlegend):
No
OpenStudy (anonymous):
what it, i can work backwords from the answer at this point and i think understand better
OpenStudy (mathlegend):
A= 15
B= -13
C= 2
A*C= 30
+B= -13
The two numbers that add to -13 but when multiplied that equal 30 are what?
OpenStudy (anonymous):
-10 -3
OpenStudy (mathlegend):
Okay so when we rewrite the equation what do you get?
15x^2-3x-10x+2
right? Notice I just split up the -13
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OpenStudy (anonymous):
yess i get that
OpenStudy (mathlegend):
15x^2-3x-10x+2
So now find the common factors. Take the two first numbers and factor those. Then the last two.
15x^2-3x (Can you factor that?)
-10x+2 (Can you factor that?)
OpenStudy (mathlegend):
Okay for 15x^2-3x
the greatest number that goes into both of them is what?
OpenStudy (anonymous):
3
OpenStudy (mathlegend):
Good, but lets say 3x since both numbers have at least one 'x'.
15/3 = ?
-3/3 = ?
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OpenStudy (anonymous):
what is the answer to it? i am really confused and this problem is due in 10 min :/
OpenStudy (mathlegend):
3x(5x-1)
Then you would factor out -10 and 2
OpenStudy (mathlegend):
-2(5x-1)
OpenStudy (mathlegend):
So combining those you would get
3x(5x-1)-2(5x-1)
OpenStudy (mathlegend):
Now you take the numbers outside of the parentheses and put those together and the inside comes after.
(3x-2)(5x-1)
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OpenStudy (mathlegend):
That is your answer....
OpenStudy (anonymous):
is says thast wrong when i type it in
OpenStudy (mathlegend):
What are you typing it into?
OpenStudy (anonymous):
xyz.com im doing homework
OpenStudy (anonymous):
xyz homework
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OpenStudy (mathlegend):
Okay what do they say is the answer?
OpenStudy (anonymous):
they dont tell you it just says wrong
OpenStudy (mathlegend):
Okay one sec
OpenStudy (anonymous):
kk
OpenStudy (mathlegend):
Okay common mistake
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OpenStudy (mathlegend):
I'll give you the answer to submit
OpenStudy (mathlegend):
( 5x - 1 )( 3x - 2 )
OpenStudy (anonymous):
thanks you for all the help, sorry i didnt quite catch on to this problem
OpenStudy (mathlegend):
Does it say that is right?
OpenStudy (anonymous):
yea
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OpenStudy (mathlegend):
You know the strange thing is I gave you
(3x-2)(5x-1)
which is actually the same as
(5x-1)(3x-2)
That computer must not know about the Commutative Property