Question

differentiate: y=(2x^3-4x+1)^2/3

Answer 1

do you know how to use the chain rule..?

Answer 2

no

Answer 3

ok... that make it very hard... because thats what you need for this question

Answer 4

haay :/ how to use that ?

Answer 5

the chain rule is \[\frac{dy}{dx} = \frac{dy}{du} \times \frac{du}{dx}\]

you would need to let

\[u = 2x^3 -4x + 1\]

and \[y = u^{\frac{2}{3}}\]

Answer 6

can you find du/dx...?

and dy/du..?

Answer 7

is that ?