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(9a^2)/3a+b-b^2/3a+b simplify to lowest terms
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3 a+1/(3 a)
\[\frac{9a^2}{3a+b}-\frac{b^2}{3a+b}\] like that?
correct
denominators are the same, so the first step is to add in the numerator, keep the denominator
second step is to factor the numerator it is the difference of two squares third step is to cancel
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9a^2-b^2/3a+b
that is step one now you need to factor the numerator
is it???
plz...sir give me medal fr that question..
is that question sir u said
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these last steps are what I am struggling with
sry!!1
so whatt is 9a^2-b^2 factored
trying
k thanks
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\(x^2-y^2=(x+y)(x-y)\)
sry!! can't solve
ok satellite73 whats the final answer here please
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