Question

What do I need to do to get
\[\frac{ c }{ a }-\frac{ b^2 }{ 4a^2 }\]=\[\frac{ 4ac-b^2 }{ 4a }\]

Answer 1

u cant lol

Answer 2

these 2 expressions are not equal

Answer 3

I mean equal, I am trying to prove the quadratic formula by completing the square.

Answer 4

*dont

Answer 5

and my text say the first expression can be manipulated into the second.

Answer 6

\[\frac{ c }{ a }-\frac{ b^2 }{ 4a^2 }=\frac{4ac-b^2}{4a^2}\]

Answer 7

ok how?

Answer 8

@telltoamit

Answer 9

c/a can be written as 4ac/4a^2

Answer 10

how did this get a medal, I am know the wiser.

Answer 11

hehee lol

Answer 12

\[\frac{ c }{ a }-\frac{ b^2 }{ 4a^2 }\] 1. Multiply first fraction by 4a/4a to get:
\[=\frac{4ac}{4a^2} -\frac{b^2}{4a^2}\] 2. Combine fractions to get:
\[=\frac{4ac-b^2}{4a^2}\]3. You're finished