What are the x- and y – intercepts of the following equation: y = -0.05x + 16 (16, 0), (0, 320) (0, 16), (32, 0) (0, 16), (320, 0) (16, 0), (-320, 0)
the method for finding intercepts is, if you think about it you can just substitute. when x = 0 what is the y value, and when y= 0 solve for x
the simplest one is when x = 0 because that leaves y = 0 +16 so y = 16 now when y = 0 0 = -.05x +16
and also a function in the form of y=mx+b (like you have) the 'b" is simply your y intercept, (when x=0)
precisely . which happens when x=0
do you know how to solve 0=0.05x +16 for x?
the numbers bellow are the answers i can use i understand what your trien to say but hpw do i get the answer?
the answers are giving you the ordered pairs for the answer. for example as shown above when x=0 y=16 so the answer for the x intercept is (0,16) and if you solve for when y=0 your answer will be of the form (x value, 0) and that x value is when was solved for when y=0
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