Question

Help Please! Perform the indicated operation 5 1/6 - 2 2/3
I did the math (in comment) but it doesn't seem to be right

Answer 1

\[\frac{ 1*3 }{6*3 } - \frac{ 2*6 }{3*6 } = \frac{ 3 }{ 18 } - \frac{ 6 }{ 18 } \]
I get 3 3/18 but the answers have 2's. I need help :(

Answer 2

where did 5 and 2 go in your calculation?

Answer 3

u cannot just do 5-2=3

Answer 4

Oh? how would I add them into the equation then?

Answer 5

ok,
\[5\frac{1}{6}=\frac{5*6+1}{6}=\frac{31}{6}\]
can u do the same for 2 2/3 ??

Answer 6

So I would add the 2 in with the equation like you did? But, how does a two at the end come into play?

Answer 7

Evaluate the following:\[\left(5+\frac{1}{6}\right)-\left(2+\frac{2}{3}\right) \]

Answer 8

i got 12/3 for the 2 2/3 one

Answer 9

wait,i would tell that my method was lenghty,and u can do 5-3=2
as far as your work in 1st comment,the only mistake u did was 6*2=6
its actually 12

Answer 10

im lost now

Answer 11

so whats
\[\frac{3-12}{18}\]

Answer 12

-9/18

Answer 13

\[\frac{ 1*3 }{6*3 } - \frac{ 2*6 }{3*6 } = \frac{ 3 }{ 18 } - \frac{ 12}{ 18 } =\frac{-9}{18}=\frac{-1}{2}\]
got this?

Answer 14

\[2+\frac{2}{3}=\frac{2*3}{3}+\frac{2}{3}=\frac{2*3+2}{3}=\frac{8}{3} \]

Answer 15

Ok, then where does the big two come from?

Answer 16

\[a+\frac{b}{c}=\frac{a c+b}{c} \]

Answer 17

2 1/3. 2 1/2. 2 1/6. those are the options

Answer 18

ok,5-2=3
so your final answer would be 3 -1/2
which is same as
(6-1)/2
=5/2
=2 1/2

Answer 19

Oh, so the negative is what makes the 3 a 2?

Answer 20

\[\left(5+\frac{1}{6}\right)-\left(2+\frac{2}{3}\right)=\left(\frac{31}{6}\right)-\left(\frac{8}{3}\right)=\left(\frac{31}{6}\right)-\left(\frac{16}{6}\right)=\frac{15}{6}=\frac{5*3}{2*3}=\frac{5}{2} \]

Answer 21

Do you know how to change \[
2 \frac{2}{3} \]
to an improper fraction?
2 can be changed to \(\frac{6}{3} \)
so 2 +2/3 is the same as 6/3 + 2/3= 8/3