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A fuse has a length of 10 meters and burns at a rate of two centimetres per second when lit. What length of fuse (in cm) remains after t seconds and when will it totally burned out?
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@amistre64, @Hero
Hint: D = rt
can we use calculus?
You should always try to solve a problem without calculus if it isn't necessary
would it not be something like 10-0.02t
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it burns at a rate of 4 cms; so im sure we can if we need to
2cm*s^-1
for some reason i read it as lit at both ends lol
D - rt = 0
right, so 10m - 0.02cm*s^-1*t
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D=10m - 0.02cm*s^-1*t
\[\frac{df}{dt}=-.02\] \[f(t)=-.02t+C\]initial condition f(0)=10
right, so when will it be totally burned out?
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