the perimeter of a retangular sign is not to exceed 50ft. the length is to be twice the width. what widths will meet these conditions?
do you know the formula for the perimeter?
....?
doesnt sy that is all the question that it gives
but yoy should know that P=2l+2w
i havent been in class long and dont know anything about algebra lol
im 35 trying to go back to school
ok:) if l is the length of the rectangle w is its width then P=2l+2w the length is twice the width=>l=2w then the perimeter becomes:P=2(2w)+2w=6w i hope you're following so far?
yes i am thanks
ok,it says the perimeter is not to exceed 50 which means P<=50 ( less than or equal to) =>6w<=50 =>w<=50/6 w<=25/3 this means all widths which are less than or equal to 25/3 ft are accepted
wow
so thats my answer?
yes its not only one answer cause its an inequality:)
oh ok i understand now .. just wish i could understand how you did all that lol im going to write it down andd see if i can do it lol...thank you
ok,if you have any questions,just ask:)
ok thanks i will
convert to a percent 0.00763 isnt that move dec 2 times to the right?
or the left?
to the right,or multiply by hundred
763%
0.763%
one by one...% to decimal 2 places to the left
k thanks
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