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3 over g^-2h^3
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Hint: \[\large \frac{1}{n^{-a}} = n^a \]
that doesnt really help :/
But you have a negative exponent in the denominator, no?
yes . but im still confused
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If you have a negative exponent in the denominator, what is so confusing about moving it to the numerator and removing the negative? Because that's what the rule I just showed you states to do.
Okay but the numerator isn't one . its 3 . so where does the 3 go ?
\(g^{-2}\) is the negative exponent. Move that to the numerator and remove the negative.
Can you also help me with this one ?
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