Question

using identities simplify :
(sin^2x-4cos^2x)/1-5cos^2x

Answer 1

@Hero @satellite73

Answer 2

dangit no one wants to try this one lol @lgbasallote

Answer 3

how is the question? \[\huge \frac{\sin^2 x - 4\cos ^2 x}{1 - 5\cos^2 x}\]
???

Answer 4

looks correct

Answer 5

change sin^2 x into cos^2 x first
\[\huge \implies \frac{ 1 - \cos^2 x - 4\cos^2 x}{1 - 5\cos^2 x}\]
combie like terms
\[\huge \implies \frac{1 - 5\cos^2 x}{1 - 5\cos^2 x}\]
simplify
\[\huge \implies \frac{\cancel{1 - 5\cos^2 x}}{\cancel{1 - 5\cos^2 x}} \implies 1\]
does that help?

Answer 6

oh your good lol

Answer 7

heh i bet you knew this all along