Question

4x^3 - 12x = 0

Answer 1

4x is a common factor so factor that out first
\[\implies 4x(x^2 - 3) = 0\]
now equate the factors to zero
\[\implies 4x = 0 \quad ; \quad x^2 - 3 = 0\]
now solve for x
\[\implies \frac{4x}4 = \frac 04 \quad ; \quad x^2 = 3\]
\[\implies x = 0 \quad ; \quad x = \pm \sqrt 3\]
does that help?

Answer 2

The first part I get like 4x=0 but for x^2 - 3 = 0, isn't that supposed to be like (x+3)(x-3)=0? Then x=+/- 3?

Answer 3

no. (x+3)(x-3) is x^2 - 9

Answer 4

x^2 - 3 is \((x + \sqrt 3)(x - \sqrt 3)\) if you want to write it like that

Answer 5

Ohhh! Okay, okay! I understand it now! Thank You!

Answer 6

welcome