Question

ln(7x)=11

Answer 1

change to log firm first
\[\implies \log_e (7x) = 11\]
change to exponential form
\[\implies e^{11} = 7x\]
divide bopth sides by 7
\[\implies \frac{e^{11}}{7} = x\]
does that help?

Answer 2

not really still confused

Answer 3

where?

Answer 4

Do you know how to work with logarithms with real number bases?
IE:
\[\log_{2}8 = 3\]
Here "ln" simply means a logarithm with a base of 'e'.

Answer 5

ok lemme try
write both sides in the power of e
\[\Large e^{\ln(x)}=e^{11}\]
this is ok with you till now ?

Answer 6

Thanks guys I think I've got it now.!

Answer 7

yw:)