Question

[x^2-9]/[x-2]
HA:=3
VA:= -3
OA:= 2
Are these correct?

Answer 1

what's OA? original asymptote?

Answer 2

oblique

Answer 3

hmm one slight mistake...VA should be 2

Answer 4

because you equate x - 2 to 0 then solve for x so x = 2

Answer 5

assuming VA is vertical asymptote

Answer 6

ty. ahh very good
x^2-16/6x-24
disct = x can not = 4
is that correct?

Answer 7

disct means discriminant?

Answer 8

discontinuities

Answer 9

oh lol

Answer 10

yes x = 4 is a removable discontinuity

Answer 11

so it can not = 4?

Answer 12

or it does

Answer 13

but can not = -4

Answer 14

[x^2-x-12]/[x-4]
disc.= -3
x int=(3,0)
y int= (0,-3)
shape= straight line

are these correct?