Question

Find the equation of a straight line through points (2,6) parallel to the line with equation 2x+5y=1

Answer 1

Okay first you want to get that equation into slope intercept form
y=mx+b

Answer 2

Can you do that?

Answer 3

2x+5y=1
How do you get the 2x to the other side?

Answer 4

so 5y = 1-2x?

Answer 5

Well remember we want it in a specific order... y=mx+b
5y=-2x+1

Answer 6

Now how we get rid of the '5y' which is being multiplied?

Answer 7

y= (-2x+1)/5?

Answer 8

Okay so we have...
\[\frac{ -2 }{ 5}x+\frac{ 1 }{ 5}\]

Answer 9

So now we need to use the distance formula for the Coordinate points.
y-y1=m(x-x1)

Answer 10

Can you plug in the numbers?

Answer 11

y-6=-2(x-2)?

Answer 12

Remember our slope was \[\frac{ -2 }{ 5}\]

Answer 13

y-6= -2/5(x-2)

Answer 14

Now when you distribute what do you get?

Answer 15

y=-2/5x\[-6\frac{ 4}{ 5 }\]?

Answer 16

y-6=-2/5x+4/5
That is what you should have gotten.

Answer 17

ohh, sorry i put the -6 to the other side, but forgot to make it positive instead of negative

Answer 18

So now lets get the y by itself. So lets add 6 to both sides. Tell me what you get once you add 6 to both sides.

Answer 19

y=-2/5x+34/5?

Answer 20

Good that is your answer.

Answer 21

You truly are a math legend :) thankyou :)

Answer 22

No problem :)