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Mathematics 20 Online
OpenStudy (anonymous):

Hi guys, help me x^2+3x+2 for this equation how to find the possible x values?

OpenStudy (anonymous):

First, factorize the equation. Can you do that?

OpenStudy (mathlegend):

Think what numbers when added equal 3 but when multiplied equal 2?

OpenStudy (anonymous):

yes

OpenStudy (mathlegend):

So what numbers when added equal 3 BUT when multiplied equal 2

OpenStudy (mathlegend):

_+_= 3 _*_= 2

OpenStudy (mathlegend):

Fill in the blanks

OpenStudy (anonymous):

1,2 is correct?

OpenStudy (mathlegend):

Yes.

OpenStudy (mathlegend):

So now lets break down 3x x^2+1x+2x+2

OpenStudy (mathlegend):

Now lets factor

OpenStudy (mathlegend):

x^2+1x then factor 2x+2

OpenStudy (mathlegend):

Are you having trouble @nroprstar

OpenStudy (anonymous):

hi tell me more cleary yar..

OpenStudy (mathlegend):

\[x^{2}+1x+2x+2\] \[x^{2}+1x \] 2x+2

OpenStudy (mathlegend):

What do we have in common (Letters or Numbers) in the following equation \[x^{2}\]

OpenStudy (anonymous):

-1 and -2

OpenStudy (anonymous):

correct!

OpenStudy (mathlegend):

That is not the solution.

OpenStudy (anonymous):

Is not?

OpenStudy (mathlegend):

Okay look... \[x^{2}+1\] factors as... x(x+1)

OpenStudy (mathlegend):

little typo mean to post: \[x^{2}+1x\]

OpenStudy (anonymous):

No,, I am trying to find eigen values in matrix...

OpenStudy (anonymous):

k mathlegend... tell

OpenStudy (mathlegend):

2x+2 factors as what? 2(x+1) right

OpenStudy (anonymous):

My mistake, sorry. I probably was thinking of another topic.

OpenStudy (mathlegend):

So now we have x(x+1)+2(x+1)

OpenStudy (anonymous):

mm ok

OpenStudy (mathlegend):

All the outside numbers go in one set of parentheses and the inside go in another.

OpenStudy (anonymous):

s

OpenStudy (mathlegend):

(x+2)(x+1)

OpenStudy (mathlegend):

That is your answer.

OpenStudy (anonymous):

ya now I understood. thanks alot

OpenStudy (mathlegend):

No problem

OpenStudy (anonymous):

so x=-2 or -1

OpenStudy (anonymous):

@MathLegend they are asking for 'possible values of x'

OpenStudy (anonymous):

if my explanation was correct and we are talking about the same topic, x would be -2 and -1

OpenStudy (mathlegend):

oh, well, okay.

OpenStudy (anonymous):

Hold on. Let me get someone else's opinion.

OpenStudy (anonymous):

Basically MathLegend and I are thinking about the same thing...

OpenStudy (anonymous):

@experimentX

OpenStudy (experimentx):

you cannot find the value of unknown from an expression.

OpenStudy (experimentx):

you need equations ... f(x) = 0 or a system of equations..

OpenStudy (mathlegend):

Well, being what experimentX said.. then are you sure you were not supposed to just factor @nroprstar

OpenStudy (anonymous):

ahh.. okay. I was thinking of something else then. http://www.themathpage.com/aprecalc/roots-zeros-polynomial.htm

OpenStudy (anonymous):

I was looking of the values of x that would make the equation to zero.

OpenStudy (anonymous):

Sorry, @nroprstar

OpenStudy (anonymous):

They haven't given a right side so its not an equation, its an expression.

OpenStudy (lgbasallote):

these people are good @pratu043 never doubt them. they are able to *solve* expressions <bows down>

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