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What is the solution set of |x| > 12? I think its the last option x < –12 or x > 12 x < 12 x > –12 and x < 12 x > –12
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no..it's not the last option here's a hint: if you have \[|x| >1\] the solution set would be \[\pm x > 1\] or in compund inequality, \[x > 1; \; x< -1\] does that help?
Not really. I thought it would have to be the absolute value so like -12 0r 12.
Idk what the plus/minus sign is...
yes. x> 12 or -x > 12 now if i divide that second one by -1 i get x < -12 so the compund inequality is x>12 or x<-12 got it?
plus minus sign means positive/negative
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Ooooh. Okay. Thanks. I understand it a lot better now.
welcome
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