A baseball player with mass m = 79 kg, sliding into second base, is retarded by a frictional force of magnitude 470 N.
What is the coefficient of kinetic friction µ between the player and the ground? [Halliday, Resnick and Walker 2003,
112].

Question

A baseball player with mass m = 79 kg, sliding into second base, is retarded by a frictional force of magnitude 470 N.  
What is the coefficient of kinetic friction µ between the player and the ground? [Halliday, Resnick and Walker 2003, 
112].

lgbasallote · Answer

$$f = \mu k \cdot F_N$$
to solve for $\mu k$  dvide both sides by F_N
$$\mu k = \frac{f}{F_N}$$
F_N is just mg (agree?)
$$\mu k = \frac{f}{mg}$$
so now substitute
$$\mu k = \frac{470}{(79)(9.8)}$$
use a calculator to solve

does that help?

anonymous · Answer

ok i will...thank you so much :)

lgbasallote · Answer

welcome