Question

equation

Answer 1

\[ x = {-b \pm \sqrt{b^2 - 4ac} \over 2a}\]Hinty hint.

Answer 2

is my answer correct?

Answer 3

x = -2 +/- 1sqroot 13

Answer 4

No... :/

Answer 5

is it okay if you can show me the correct way?

Answer 6

\[x = {-b \pm \sqrt{b^2 - 4ac} \over 2a}\]You already know what a, b and c are... don't you?

Answer 7

yes
a = 1 b = 4 c = -9

Answer 8

Yeah, but you plug the values into the formula that I gave you.

Answer 9

http://www.mathwarehouse.com/quadratic/quadratic-formula-calculator.php

Answer 10

??

Answer 11

You can simply do that one yourself.
\[y = x + 3 \]Suppose they ask you what \(y\) is when \(x = 6\). You plug-in \(x = 6\).\[\implies y = 6 + 3\\\implies y=9 \]

Answer 12

Does that example help?

Answer 13

ok