Question

factor completely 4x^2+12x+8

Answer 1

Wud u like me to explain the concept of factorising of these types of expressions?

Answer 2

yes absolutely... i want to find out where i did these wrong, i figure them out on my end and then post it to see if i am right and then compare

Answer 3

sum = 12

Product = 32

Answer 4

find two numbers

Answer 5

let me explain it with a simple example so that u can get a gud idea of it.
Suppose u hav an expression
2x^2+5x+3
and u can see that this is of the form
ax^2+bx+c.
Nw ur
a=2. b=5 and c=3.

1.Multiply a by c and see vat u get.
In this case u will get
a*c=2*3=6
Say a*c=d=6

2.Find two numbers x and y such that
x+y=b
xy=d
In this case
x+y=5
xy=6
and
x bcomes 3 and y bcomes 2.

3.Split the middle term.
2x^2+5x+3
=2x^2+2x+3x+3

4.let us take the first two terms and factorise them.
2x^2+2x
as u can see 2x is common to both 2x^2 and 2x.
When u take it out u get x+1.
That is
2x^2+2x=2x(x+1)
let us take the last two terms and factorise them.
3x+3
as u can see 3 is common to both 3x and 3.
When u take it out u get x+1.
That is
3x+3=3(x+1)

5.Nw let us combine both the results together.
2x^2+2x+3x+3
=2x(x+1)+3(x+1)
=(2x+3)(x+1)

6.You r done.

Is that clear?
Hope u can do ur question with this idea in mind.

Answer 6

Probably 8 and 4

Answer 7

thanks yahoo but aj is helping me lol she is breaking it down for me :)

Answer 8

ah ok

Answer 9

you guys are super helpful.... and @ajprincess i get confused cuz in the session, they taught us 3 ways to solve a problem and its all one jumbled mess in my head. thanks to you as well @Yahoo!

Answer 10

oh k. my kind advice is stick to one method nd it will bcome simple

Answer 11

if only it were that simple... they gave us 3 methods and you have to figure out which method goes to each problem.. just too much

Answer 12

The one I explained is applicable for all questions of this type. If u think it simple nd feel it is really helpful u can stick to it.