Question

factor completely 8x^2+10x-8

Answer 1

use Quadratic Theorem

Answer 2

From 8x^2+10x-8, we see that a = 8, b = 10 and c = -8


Let's use the discriminant formula to see if we get perfect square or not


D=b^2-4ac


D=(10)^2-4(8)(-8)


D=100-4(8)(-8)


D=100-(-256)


D=100+256


D=356

Answer 3

Since we do not get a perfect square, we cannot factor this over the rationals.