Question

5x^2-9x-2=0 solve for x

Answer 1

use \[D=\frac{ -b \pm \sqrt{(b)^2-4ac} }{ 2a }\] where a =5,b=-9 and c=-2

Answer 2

I can't factor?

Answer 3

no i guess you can't factor..you've to use this

Answer 4

umm ok

Answer 5

i hate using the quadratic formula

Answer 6

but it's compulsion in this case

Answer 7

yea
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Answer 8

can i use x^2-9x-2=0?

Answer 9

no coefficient of x^2 is 5 ...you can't do that

Answer 10

Why not just split the middle term to get:

5x^2 -10x + 1x - 2 = 0

Answer 11

and do what?

Answer 12

Factor the first two terms, then factor the last two terms to get:

5x(x-2) + 1(x-2) = 0

Answer 13

so x=2, -1/2

Answer 14

yes

Answer 15

I saw that @ghazi

Answer 16

no wait your wrong

Answer 17

but i deleted it before somebody could have seen

Answer 18

its -1/5 and 2

Answer 19

yes that's correct