Ask your own question, for FREE!
Mathematics 9 Online
OpenStudy (anonymous):

What is the fourth term of (2x + 3y)6?

OpenStudy (anonymous):

4320x3y3 4320x4y2 4320x2y4 4320x4y3

OpenStudy (amistre64):

no ... im remebering that backwards

OpenStudy (amistre64):

6 5 4 3 begins with a 3

OpenStudy (amistre64):

eventually itll all fall into place ;)

OpenStudy (campbell_st):

no its 6C0(2x)^6(3y)^0 ... so its 6C3(2x)^3(3y)^3

OpenStudy (campbell_st):

sorry for the error

hero (hero):

Hint: Use Pascal's triangle

OpenStudy (amistre64):

the triangle is useful in the 4320 part, but thats the same on all of them

OpenStudy (anonymous):

so D?

OpenStudy (amistre64):

not d, both exponents need to be 3s

OpenStudy (anonymous):

a

OpenStudy (campbell_st):

the sum of the powers must be 6 so it can't be D

OpenStudy (amistre64):

that one suits it better yes

OpenStudy (campbell_st):

correct

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!