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Write (-x-3)(-2x-3) in standard form
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use law of distribution
\[2x^2+9x+9\]
thats what i got
cool :)
Sooo how would i find the x-intercepts
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it's a quadratic equation solve for x
How though? My math teacher is quite the retrice
\[2x^2+6x+3x+9=0\]
can you do it now?
Could you do it for me so I can double check my answer?
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what you got?
\[2x(x+3)+3(x+3)= (2x+3)(x+3)=0\]
Yeah I'm lost...
just use method of factorization and then you'll get x=-3/2 and -3
okay thanks
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:) YW
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