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Mathematics 13 Online
OpenStudy (anonymous):

Solve D=ABC. Solve for B

OpenStudy (anonymous):

Also y=bx+a also solve for b?

OpenStudy (anonymous):

2 separate problems.

OpenStudy (anonymous):

D = ABC, to seperate B, divide AC both sides y = bx + a, minus a both sides and then divide by x both sides

OpenStudy (anonymous):

So \[\frac{ d }{ ac }=b\]?

OpenStudy (anonymous):

yea

OpenStudy (anonymous):

Okay and then \[\frac{ y-a }{ x }=b\]?

OpenStudy (anonymous):

yup

OpenStudy (anonymous):

Okay... there I go again... over analyzing.. thanks!

OpenStudy (anonymous):

Go another one for ya... this one is really weird... never see one like it before. b-b1=m(k-k1)

OpenStudy (anonymous):

Solving for m

OpenStudy (anonymous):

(b-b1) = m(k-k1), divide (k-k1) both sides

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