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Solve D=ABC. Solve for B
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Also y=bx+a also solve for b?
2 separate problems.
D = ABC, to seperate B, divide AC both sides y = bx + a, minus a both sides and then divide by x both sides
So \[\frac{ d }{ ac }=b\]?
yea
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Okay and then \[\frac{ y-a }{ x }=b\]?
yup
Okay... there I go again... over analyzing.. thanks!
Go another one for ya... this one is really weird... never see one like it before. b-b1=m(k-k1)
Solving for m
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(b-b1) = m(k-k1), divide (k-k1) both sides
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