Question

find two consecutive even intergers such that the smaller added to two times the larger gives the sum of 40

Answer 1

let x be the first integer

the next consecutive even integer would be x+2

smaller added to two times the larger would be x + 2(x+2)

it says teh sum of that is 40 so...

x + 2(x+2) = 40

do you know how to solve for x now?

Answer 2

let the 1st integer be x

the consecutive even integer is x + 2

and you know

x + 2(x+2) = 40

solve for x

Answer 3

would it be 12 and 14?

Answer 4

looks good to me... well done