Factor the trinomial. 3(a + b)2 + 5(a + b) − 2
am I able to use the quadratic equation with these values??
just for sake of simplicity let x=a+b so now u have quadratic equation: 3x^2+5x-2 now u can use quad eq. .....
in the end u can resubstitute back x as x=a+b
alright, so A+B= \[(-5\pm7)/6\] where do I go from here?
my two answers lead to -2 and 1/3. How do I present my results in an answer form?
if a is the root x-a is the factor make sense?
so if x=1/3 factor will be x-1/3 or (3x-1) so (3a+3b-1) can u find other factor???
I'm failing to understand the concept. I appreciate that you're not solving the problem for me, but what did you do to transform your x-1/3 to (3x-1)?
x-1/3 = (3x-1)/3 right? since f(x)=0 was your quadratic equation, that /3 will not have any effect.
the other factor would be x+2 (a+b+2)
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