Question

Solve radical equation (please show work so i can follow)

Answer 1

\[3x=\sqrt{20-3x}\]

Answer 2

First, square both sides so you get ride of the radical. Then, make the equation into standard notation. After that, solve using quadratic equation.

Answer 3

square both sides

Answer 4

9x^2 = 20 - 3x

9x^2 + 3x - 20 =0

nw solve it is quad eq

Answer 5

An example of standard notation is \[x^2+4x+5=0\]

Answer 6

\[x={-b \pm \sqrt {b^2-4ac} \over 2a}\]

Answer 7

ohh quadratic okay. quadratic is \[b \pm \sqrt{b^2-4ac}/2a\] okay ^ thanks

Answer 8

yup.

Answer 9

you're welcome! :)

Answer 10

Soo, -9 +/- the root of 81-240/18.

Answer 11

which ended up being 9.7

Answer 12

-b

Answer 13

where a=9, b=3 and c=-20

Answer 14

hm i will try again

Answer 15

Okay.

Answer 16

now i get -9+/- 1.5. sorry i just don't understand math :\

Answer 17

oh wait i ot my answer. it's 4/3.

Answer 18

Yup.

Answer 19

:)

Answer 20

thanks!

Answer 21

You're so welcome! :)

Answer 22

awesome and i just passed a pretest for my class because of this (and some lucky guessing ;) ) you're the best dude

Answer 23

Ha ha. You're very welcome. ;)

Answer 24

Give yourself some credit to, will ya?

Answer 25

too*