The sum of two numbers is 48.One number is 3 times as large as the other. What are the numbers?
x+y=48 x=3y Now just solve for x and y (I'd use the substitution method for this one)
thats where i get confused
Which part are you confused? By substitution you substitute x=3y into x+y=48, which will become 3y+y = 48. Solve this equation to get the value of y, then use y to get x.
when it comes to breaking it down and subsitituing
You have 2 equations with 2 unknown values: x+y=48 x=3y Using the substitution method you'd take the second equation which tells you exactly what x equals and plug it into the first equation anywhere you see an x: (3y)+y=48 4y=48 y=12 Now you know what y is. Use either of the original equations plugging in y to solve for x: x + y = 48 x+12=48 (plug in y=12) x=48-12=36 Therefore, x must equal 36 and y = 12.
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