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The numbers 1 through 5 are recorded on individual slips of paper and placed in a hat. What is the probability of drawing the 3, not replacing it, and then drawing the 4?
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The odd of picking a 3 would be 1 in 5 and after that, the odds of picking a 4 would be 1 in 4...so the combined odds would be: \[\frac{1}{5}*\frac{1}{4}=?\]
because there is only one 3 so the first Q is 1/5 and the second Q is 1/4 because there is only 1 4 left in 4 numbers
so it would be 1/5 x 1/4
so 1/20?
oi
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Ken
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