Mathematics
6 Online
OpenStudy (erinweeks):
HELP PLEASE (:
What is the remainder of (x3 – 6x – 9x + 3) ÷ (x - 3)
A. -51
B. -51
x - 3
C. -17
x
D. -17
x - 3
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OpenStudy (compassionate):
(-x)-6x+(-3)3
------------- = - 7x
x - 3
OpenStudy (erinweeks):
there is no -7x ?
OpenStudy (compassionate):
What form is it in?
OpenStudy (erinweeks):
it doesnt say ? what posted was all it said .
OpenStudy (erinweeks):
A. -51
B. \[\frac{ -51 }{ x-3 }\]
C. \[\frac{ -17 }{ x }\]
D.\[\frac{ -17 }{ x-3 }\]
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OpenStudy (erinweeks):
them are the answers i can choose from
jimthompson5910 (jim_thompson5910):
Use the remainder theorem
jimthompson5910 (jim_thompson5910):
If you divide P(x) by x-k, then the remainder 'r' is
r = P(k)
OpenStudy (compassionate):
Sorry, I was solving and not giving the remainder.
OpenStudy (erinweeks):
do you guys no what the remaidder is ?
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jimthompson5910 (jim_thompson5910):
yes, what do you get for the remainder?
OpenStudy (erinweeks):
well i thought it was a but i got it wrong ..
OpenStudy (erinweeks):
-51
jimthompson5910 (jim_thompson5910):
It is -51, here's why
x^3 - 6x^2 - 9x + 3
(3)^3 - 6(3)^2 - 9(3) + 3
-51
jimthompson5910 (jim_thompson5910):
Now because the remainder is a part of the divisor (basically its what is left over), you can write "remainder -51" as -51/(x-3)
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OpenStudy (erinweeks):
but its not because i got it wrong on my test ..
OpenStudy (erinweeks):
So Could B , be the answer ?
jimthompson5910 (jim_thompson5910):
yes, if A doesn't work, then it has to be B
OpenStudy (erinweeks):
okay thank you so much !
jimthompson5910 (jim_thompson5910):
you're welcome