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3 2^x = 6 5^x solve for x
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simplify first by dividing both sides by 3: 2^x =2* 5^x now taks logs: ln 2^x = ln 2 + ln 5^x by laws of logs x ln 2 = ln 2 + x ln 5 can you continue from here
just think of ln 2 and ln 5 as numbers (which they are) so - ln 2 =( ln 5 - ln 2) x x = - ln 2 / (ln 5 - ln 2)
(ln6-ln3)/(ln2-ln5)
how do you get ln2 on top?
right - thats basically what i have
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hows does ln6-ln3 = ln2
i'm dividing both sides by ( ln5 - ln2)
ln6 - ln3 = ln 6/3
oh i get it
thank you
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yw
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