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Write the equation of a circle with a center at (5, 5) and a diameter of 13.
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(x – 5)^2 + (y – 5)^2 = 42.25 (x + 5)^2 + (y + 5)^2 = 169 (x + 5)^2 + (y + 5)^2 = 13 (x + 5)^2 + (y + 5)^2 = 42.25
it has to be between a and c
Hint: what's the distance formula (Pythagorean Theorem)?
not sure.. :/
number on the right = r^2 (radius squared) and radius = half diameter
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ok...
soo 13^2?
noo - 13 = diameter
so half of 13
6.5?
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general equation of circle is (x-a)^2 + (y-b)^2 = r^2 yes r = 6.5
thats not one of the choices though
(a,b) is center
r^2 not r
6.5^2
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ok! i see....so it would be d not a correct?
@cwrw238 ?
its (x-a)^2 right? and a = 5 so thats (x-5) is that a or d?
A
thanks @cwrw238
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yes
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